Hmf.readthedocs.io Website Review

hmf is a python application that provides a flexible and simple way to calculate the Halo Mas* Function for a range of varying parameters. It Calculate mas* functions and related quantities extremely easily. Caching system for optimal parameter updates, for efficient iteration over parameter space. Focus on flexibility in models. Each “Component”, such as fitting functions, filter functions, growth factor models and transfer function fits are implemented as generic clas*es that can easily be altered by the user without touching the source code. Focus on simplicity in frameworks. Each “Framework” mixes available “Components” to derive useful quantities – all given Comprehensive in terms of output quantities: access differential and cu*ulative mas* functions, mas* variance, effective spectral index, CLI scripts both for producing any quantity included, or fitting any quantity. hmf is built on several other packages, most of which will be familiar to the scientific python programmer. All of these dependencies You will only need emcee if you are going to be using the fitting capabilities of hmf. The final, optional, library is pycamb, which can At present, versions of CAMB post March 2013 are not working with pycamb. Please use earlier versions until further notice. Finally the hmf package needs to be installed: pip install hmf. If you want to install the latest build (not necessarily stable), grab it Once you have hmf installed, you can quickly generate a mas* function by opening an interpreter (e.g. IPython) and doing: >>> from hmf import Mas*Function >>> hmf = Mas*Function() Note that all parameters have (what I consider reasonable) defaults. In particular, this will return a Sheth-Mo-Tormen (2001) mas* function can be input, either cosmological or otherwise. The best way to see these is to do We can also check which parameters have been set in our “default” instance: To change the parameters (cosmological or otherwise), one should use the update() method, if a Mas*Function() object already exists. For