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A common python programming problem given for beginners is to draw a diamond shape using star character as an ASCII art. For example, the following shows a diamond shape as ASCII art consisting of 9 rows, From the pattern it can be seen that the smallest diamond is of 3 rows and symmetric diamonds of this shape will have odd number of rows. For example, you can draw diamonds with 3, 5, 7, 9, 11 etc. rows. Looking at the diamond we can see that it is composed of varying numbers of stars and spaces. The number of stars increase and spaces decrease starting from the top and then from the middle row onwards the number of stars decrease and spaces increase. Now let us try to write a python program which will print a diamond given the odd number of rows required in it. Writing this in python requires us to logically think about the solution and then use python programming structures such as loops to generate the ASCII diamond row. We will split the problem by first printing half the diamond up to the middle row and then printing the bottom portion of the diamond # Number of rows needed in the diamond drawn # This needs to be an odd number # First let us draw till middle row (upper diamond) # Note that python range excludes the upper limit. # Now draw below the middle row (lower diamond) # Note that we have one row less to print We draw the diamond in two separate steps. In the first step we draw the upper diamond up to the middle row. For drawing this we first find how many spaces we need to draw and then how many stars we need to draw. This is repeated until the middle row. For the second half of the diamond we repeat the same process. However, there is a difference in calculation of the number of spaces and stars since spaces increase and star numbers decrease in the bottom section of the diamond. Please refer to the comments provided Azure vault offers a highly secure way of storing secrets used in your applications. Azure vault natively supports keys used in encryption,