Standarddeviationcalculator.net Website Review

enter values separated by comma's (ie. 5, 12, 13) this calculator calculates both sample standard deviation and ∑ = the sume of each calculation; (xi - μ)2 for each value i xi = value for each number within the dataset (i just represents the μ = the average for the values in the dataset n = the number of values in the dataset, if you have 10 numbers in the 23, 34, 14, 23, 12, 33, 13, 16 step 1. find the mean this value is also known as your average or μ this is completed by subtracting your average (or μ )from each of your values from the data set there are 8 values in the set, so you will divide by 7(n-1)  540 ÷ 7 = 77.1429 you have just solved a standard deviation problem!...now to tackle how to understand what it means. it is important to note that finding the population standard deviation has the same exact formula as the sample standard deviation, with one exception. rather than subtracting 1 from n (number of values in the denominator), you only divide by n. an example of a problem to find the standard deviation of a population is as follows: presume our data consists of the following ten values: 2, 3, 5, 5, 6, 8, 8, 9, 9, 10 step 1. find the mean to find this we find the sum of the values and divide by 10 step 2. find the difference and square them to find the standard deviation of the population you must find the difference of each value by subtracting it from the mean and squaring the result of each value. (2-6.5)= (-4.5)^2= 20.25      (3-6.5)= (-3.5)^2= 12.25 (5-6.5)= (-1.5)^2= 2.25      (5-6.5)= (-1.5)^2= 2.25 (6-6.5)= (-.5)^2= .25      (8-6.5)= (1.5)^2= 2.25 (8-6.5)= (1.5)^2= 2.25      (9-6.5)= (2.5)^2= 6.25 (9-6.5)= (2.5)^2= 6.25      (10-6.5)= (3.5)^2= 12.25 step 3. find the sum of values from step 2 and divide next you will need to determine the average of the sum of these values and then (20.25 + 12.25 + 2.25 + 2.25 + .25 + 2.25 + 2.25 + 6.25 + 6.25 + 12.25) ÷ 10 = 6.65 step 4. square root the square root of 6.65 is 2.57876, which is your population standard deviation.