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i currently have several intern openings for de*p learning and computer vision. . this is an internship for both research and development. . you will have opportunities to publish high level papers in computer vision and de*p learning, or develop cool real world ai application if. if you have experiences in de*p learning and computer vision, and interested in this intern, please send me your resume by email (xperzy. additive number is a string whose digits can form additive sequence. a valid additive sequence should contain at least three numbers. except for the first two numbers, each subsequent number in the 112358 is an additive number because the digits can form an additive sequence: 1, 1, 2, 3, 5, 8. 1 + 1 = 2, 1 + 2 = 3, 2 + 3 = 5, 3 + 5 = 8 199100199 is also an additive number, the additive sequence is: 1, 1 + 99 = 100, 99 + 100 = 199 note: numbers in the additive sequence cannot have leading zeros, so given a string containing only digits '0'-'9', write a function to determine if it's an additive number. i use the string manipulation to handle the case when the number is too larger to be stored in an long long type (in cpp). this is implemented in the checkeq function shown in my code below. note that, the question is not allowed to use 03, 02, ect format, we also have to eliminte such cases (by the if condition in line 6 below). in my implementation, the swap operation is to make the longer number always stores in a. the line 5 is to ignore the check if the two numbers a and c are totally different, regarding to the fact that the sum of two numbers will not exceede the max length of two numbers + 1. e.g., a = 998, b = 80, c = a + b = 998 + 80 = 1078 the length of c will never be greater than length of a + 1, since the carry will never greater than 1. using this properties of sum operation, we could easily implement the following code for checking the sum of three strings as shown in checkeq function. do not forget next we are facing the main part of the problem: find a way to check the whole string. i will show how i handle this in a clear way (which